Write an equation of the line passing through each of the following pairs of points. a) (−10, 4), (2, −5) b) (5, 7), (−6, −3)

The required equation of the line passing through the coordinates  (−10, 4), (2, −5) is 4y+3x = -14

The required equation of the line passing through the coordinates (5, 7), (−6, −3) is 11y-10x = -27

The formula for finding the equation of a line is expressed as:

Given the coordinates (−10, 4), (2, −5)

Get the slope:

Get the required equation

b) For the equation of the line with the coordinates (5,7) and (-6, -3)

Get the slope

m = -3-7/-6-5

m = -10/-11

m = 10/11

The required equation will be:

y - 7 = 10/11(x-5)

11(y-7) = 10(x-5)\

11y - 77 = 10x - 50

11y - 10x = -50 + 77

11y - 10x = -27

Hence the required equation of the line passing through the coordinates (5, 7), (−6, −3) is 11y-10x = -27

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let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!