Find the X and Y for the given kite

Step-by-step explanation:

PQ = QR                  Property of a kite

x + 4 = 13                 Subtract 4 from both sides

x = 13 -4                   Combine the right.

x = 9

3y+5 = x + 11             Put 9 in for x

3y + 5 = 9 + 11          Combine the right side

3y + 5 = 20               Subtract 5 from both sides

3y = 20 - 5                Combine the right

3y = 15                       Divide by 3

3y/3 = 15/3

y = 5

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}