How much current is flowing in a wire 4.55 m long if the maximum force on it is 0.575 N when placed in a uniform 0.0700-T field?

1.81A

The magnitude of the magnetic force (F) acting on a current carrying wire is given by;

F = I x L x B sin θ      (i)

Where;

I = current on the wire

B = magnetic strength

L = length of the wire

θ = angle between the wire and the magnetic field

From the question, there is a maximum force (F = 0.575N) of on the wire. This means that the angle between the wire and the magnetic field is 90°.

Also;

the magnetic field(B) = 0.0700-T

the length(L) of the wire = 4.55m

Substitute these values into equation (i) as follows;

0.575 = I x 4.55 x 0.0700 x sin 90°

0.575 = I x 4.55 x 0.0700 x 1

0.575 = I x 0.3185

Solve for I;

I = 0.575 / 0.3185

I = 1.81A

Therefore, the current flowing in the wire is 1.81A

think about the oscillation of the toy shown in the video. when the toy is at the highest point of its motion, its velocity is zero and its acceleration is negative.

the answer would be c. motion and direction

i hope this : )