What are the roots of the equation x² + 6x + 13 = 0 in simplest a + bi form? please someone help me bro im so bad at trig

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)

2/3=10/15

1/5=3/15

10+3=13/15

2 13/15 is the answer