In the given figure triangle ABC, AC=100, CB= 50 , then find the value of x? Please solve me before 10:50 AM.

Step-by-step explanation:

Given that

∆ABC is a right angled triangle

angle B = 90°

BC = 50 units

Hypotenuse (H) = AC

AC = 100 units

We know that

Cos A = Adjacent side to angle A / Hypotenuse

→Cos x = BC / AC

→Cos x = 50/100

→Cos x = 1/2

→Cos x = Cos 60°

.°. x = 60°

Hence, the value of “x” is 60°

also read similar questions: In triangle ABC, E is the midpoint of AC and D is the midpoint of CB. if DF is parallel to BE, find the length of side AB.

Points B, D, and F are midpoints of the sides of triangle ACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale. For my answer I put 32 because df is p...

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a