In the rectangular trapezoid ABCD AC is driven by a CD (see figure). Find the area of the trapezoid if AC = 3, AD = 5.

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

25=9+

=25-9=16

Now

Area of rectangle Δ ACD=

similarly,

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+

Step-by-step explanation:

just needed some points but try socratic

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: