Mathematics, 10.11.2021 19:20, hihowareyou12

2. -1
х
0
1
2
3
4
h(x) = x + 1, for -25x32
f(x) -3
-2
-1
0
1
2
y-intercept Slope
Domain
Initial (starting)
value of f(x)
Range
1
f(x) y to 4 -3 to 2
4
h(x) -2102 1/103
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2. -1
х
0
1
2
3
4
h(x) = x + 1, for -25x32
f(x) -3...