Need help on number 6 and 7 I am not good at algebra in the slightest

For #6:

I believe the answer is 1) −15x^3y^3−3x^3y^2

For # 7:

I got 3) 3

First, in order to isolate the variable "x"  you need to distribute:

13x - 2(x + 4) = 8x + 1

13x -2x - 8 = 8x + 1

Then you need to combine like terms

13x - 2x - 8 = 8x + 1

11x - 8 = 8x + 1

Add 8 to both sides

11x = 8x + 9

Subtract 8x on both sides

3x = 9

Now you can divide both sides by 3...

Thus x = 3

I'm actually taking algebra right now and I gotta admit algebra is tricky for sure. However, I think it'll get easier with practice  :D

my acc plz

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204