The base of an isosceles right triangle is 50 cm. What is its area? No spamming

So the area of an Isosceles Right Triangle = S2/2 square units. The general formula for finding out the area of any given triangle is the sum of all its sides. Thus, a triangle with side length X, Y and Z the perimeter would be: Perimeter of a triangle = X+Y+Z units.

Step-by-step explanation:

50m^2=(x^2)+(x^2)

50m^2= 2x^2

x^2=50/2

x^2=25

x = sqrt(25)

x = 51

it is base area

hope it helps

what is all that apply?