How many 3 digit codes are possible that do not contain the number 3?

729

Step-by-step explanation:

Including 3, there are 10 digits, from 0 to 9.

If you exclude 3, then there are 9 digits.

Each code will have a first digit, a second digit, and a third digit.

Each of those three digits can be chosen from 9 different digits.

We use the counting principle, and we multiply the number of possible digits for each position in the code.

number of possible first digits * number of possible second digits * number of possible third digits =

= 9 * 9 * 9 = 729

729

yor answer is 7/6 times 5

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph