A bank offer 3% interest each yr you invest 1500. Write a equation to model this situation for x years. How much will be in the account after 10 years?

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 1500

r = 3% = /100 = 0.0

n = 1 because it was compounded once in a year.

t = x years

Therefore, the equation to model this situation is

A = 1500(1 + 0.03/1)^1 × x

A = 1500(1.03)^x

When x = 10 years, then

A = 1500(1.03)^10

A = $2016

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high