Solve the system of equations. x = 3y+1
2x+4y=12
A. (10, 3)
B. (1, 4)
C. (4, 1)
D. (3, 10)

Step-by-step explanation:

C. (4,1)

When x=4 and y=1, the equations become,

4 = 3*1 +1

4=4

2*4+4*1 = 8+4 = 12

option C

Step-by-step explanation:

x = 3y + 1      equation(i)

2x + 4y =12    equation(ii)

First working for equation (ii)

substituting the value of x in equation (ii)

2(3y + 1) + 4y = 12

6y + 2 + 4y = 12

10y = 12 - 2

y = 10/10

y =1

now substitute the value of y in equation (i)

x = 3*1 = 1

x=3 + 1

x = 4

therefore , answer is (4,1)

answer: what if i dont want to show my work boi.

step-by-step explanation: im watching dbz and eating popcorn leave meh alone

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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