Point A is located at negative 4 over 6 and point B is located at negative 1 over 6 . What is the distance between points A and B? a
negative 4 over 6 minus negative 1 over 6 = negative 3 over 6 ; therefore, the distance from A to B is absolute value of negative 3 over 6 equals negative 3 over 6 units

b
negative 4 over 6 minus negative 1 over 6 = negative 3 over 6 ; therefore, the distance from A to B is absolute value of negative 3 over 6 equals 3 over 6 units

c
negative 4 over 6 plus negative 1 over 6 = negative 5 over 6 ; therefore, the distance from A to B is absolute value of negative 5 over 6 equals 5 over 6 units

d
negative 4 over 6 plus negative 1 over 6 = negative 5 over 6 ; therefore, the distance from A to B is absolute value of negative 5 over 6 equals negative 5 over 6 units

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.

134.6 us dollars

step-by-step explanation:

1 us dollar = 1.33 canadian dollars

so, 150 us dollars = 150 × 1.33 = $199.5.

in canada, the money mitchell spent = 20 canadian dollars.

remaining canadian dollars with him = 199.5 - 20 = 179.5.

after mitchell returned to us, he exchanged the remaining canadian dollars to us dollars.

179.5 canadian dollars = 179.5 × 0.75 = 134.6 us dollars.

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft