Mick is building a slide for a new park. He wants the height of the slide to be 4 feet, and he wants the horizontal distance along the ground to measure 12 feet. After building the slide, Mick decides the slide needs a vertical safety support and wants to use a 2-foot piece of wood to build the support. How far from the point where the base of the slide meets the ground should Mick place the vertical support?

x/3-10=8

x/3=18

x=48

cant see photo

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen