Physics, 04.02.2022 01:00, RidhaH

An 8cm tall object is 15cm away from a lens and produces a real image that is twice the size of the object. A. Use the lens equation to calculate the focal length of the lens

B. If the same object were in the same position in front of a lens that had the same focal length as the one above, but was a diverging lens, how tall would the image be?

C. Now assume that the object is 6.0cm in front of the original converging lens. How tall will the resulting image be?

Answers: 1

Show answers

Other questions on the subject: Physics

Physics, 22.06.2019 04:50, andrewsaul04

The position of a crate sliding down a ramp is given by x=(0.05t^3) m, y=(1.7t^2) m, z=(6−0.85t^5/2) m, where t is in seconds. (a) determine the magnitude of the crate's velocity when t = 2 s. (b) determine the magnitude of the crate's acceleration when t = 2 s.

Answers: 2

continue

Physics, 22.06.2019 10:20, coollid876

What determines the amount of inertia an object has

Answers: 2

continue

Physics, 22.06.2019 14:40, allenpaietonp9v8sv

What is the orbital period of a spacecraft in a low orbit near the surface of mars? the radius of mars is 3.4×106m.

Answers: 2

continue

Physics, 22.06.2019 16:10, amastriano6192

Ain is , is 's of ? 0.62 0.79 1.27 1.50