What is an equation of the line that passes through the point (-8,0) and is parallel to the line x+2y=14?

y=-1/2x-4

Step-by-step explanation:

Hi there!

We're given the equation x+2y=14 and we want to find a line that is parallel to it and passes through (-8,0)

Parallel lines have the same slopes, but different y intercepts.

So let's find the slope of x+2y=14

we do this by converting x+2y=14 from standard form (ax+by=c where a, b, and c are integers) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept).

for x+2y=14, to convert to slope-intercept form, start by subtracting x from both sides

2y=-x+14

divide both sides by 2

y=-1/2x+7

so the slope of x+2y=14 is -1/2

The slope of the new line (the one parallel to x+2y=14 and passes through (-8,0) will also have a slope of -1/2).

Here's the equation of that line so far:

y=-1/2x+b

we need to find b (y intercept)

as the equation will pass through (-8,0), we can use it to solve for b

substitute -8 as x and 0 as y

0=-1/2(-8)+b

multiply

0=4+b

subtract 4 from both sides

-4=b

substitute into the equation

y=-1/2x-4

Hope this helps! :)

fdvs

step-by-step explanation: vsfdvsfvd

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)