Help, anyone can help me do quetion.​

Step-by-step explanation:

PQRS is a parallelogram with QR = 6 cm, QT = 3 cm and ∠PSR = 115°.

a). By the property of a parallelogram,

   "Diagonals of a parallelogram bisect each other"

   QT = TS

   QS = 2(QT)

         = 2(3)

         = 6 cm

b). "Adjacent angles of a parallelogram are supplementary"

     m∠PSR + m∠SRQ = 180°

     115° + m∠SRQ = 180°

     m∠SRQ = 65°

c). Since, SQ = SR = 6 cm

    m∠QSR = m∠SRQ [Opposite angles of the equal sides of an isosceles triangle]

    m∠QSR = 65°

    By applying triangle sum theorem in ΔQSR,

    m∠SQR + m∠QRS + m∠QSR = 180°

    m∠SQR + 65° + 65° = 180°

    m∠SQR = 50°

addition

step-by-step explanation:

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