In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0 respectively. If the coefficient skewness is , use the information to answer

questions 9 and 10.

9. What is the approximate value of the third quartile

(Q3 ), correct to 2 decimal places?

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--- The third quartile

-- Variance

Step-by-step explanation:

Given

-- First quartile

--- Median

--- Mean

--- Coefficient of skewness

Solving (9): The third quartile

This is calculated from

So, we have:

Cross Multiply

Open bracket

Collect like terms

Divide both sides -1.38

--- approximated

Solving (b): The variance

First, calculate the standard deviation from:

So:

Make SD the subject

So, the variance is:

41*67/2=1373.5

step-by-step explanation:

i just used a calculator

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x