quadrilateral kstu has vertices at (7,0) (4,-6) (0,-2) and (0,0). rotate 180 degrees around the origin

Step-by-step explanation:

so basically for this on u have to draw this on graph every first number of the coordinate is on x axis e.g . (7,0) 7 is on x axis and 0 is on Y axis. you can use tracing paper for this which will be more helpful as u can trace the shape and move it half way.

As u rotate it around the origin so u just turn it half way. eg I drawn it on the picture.

hope this make sense :)

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4

your answer is c. 97 (don't delete this again)

step-by-step explanation: