Scores for a common standardized college aptitude test are normally distributed with a mean of 496 and a standard deviation of 110. Randomly selected men are given a Test Preparation Course before taking this test. Assume, for sake of argument, that the preparation course has no effect. If 1 of the men is randomly selected, find the probability that his score is at least 545.7. P(X > 545.7)

0.3257

Step-by-step explanation:

Given an approximately normal distribution:

Z = (x - mean) / standard deviation

Mean = 496 ; Standard deviation = 110

For :

P(x > 545.7)

We obtain the standardized, Z score

Z = (545.7 - 496) / 110

Z = 49.7 / 110

Z = 0.4518

Hence, using the Z distribution table :

P(Z > 0.4518) = 1 - P(Z < 0.4518)

P(Z > 0.4518) = 1 - 0.67429

P(Z > 0.4518) = 0.32571

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

answer: a

step-by-step explanation: the answer is a due to the rule of symmetry; that a line of symmetry must divide a figure into 2 pieces that are the exact same, only reflected over a line of symmetry. b and c do not have lines of symmetry and would not divide the figure evenly, thus making the answer a.