The difference between two positive numbers is 7 and the difference between thes cubes is 805. If 'A' represents their product and 'B' represents the sum of their squares,
find the value of 'A-B'.​

The  difference between two positive numbers is 7 and the difference between these  cubes is 805. If 'A' represents their product and 'B' represents the sum of their squares,

So,

Let the number be n and m

A = n × m = nm

B = n² + m² = (n + m)²

Now

n³ - m³ = 805

(n - m) (n² + m² + nm) = 805

Since difference is 7

7 × n² + m² + nm = 805

n² + m² + nm = 805/7

n² + m² + nm = 115

(n² + n) + (m² + m) = 115

A + B = 115

Now

On squaring the first eq.

(n - m)² = (7)²

(n - m)² = 49

B - 2A = 49

Now

A + B - B + 2A = 115 - 49

A + 2A = 66

3A = 66

A = 66/3

A = 22

By using 2

B - 2(22) = 49

B - 44 = 49

B = 49 + 44

B = 93

A - B = 22 - 93 = -71

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: