The area of triangle ABC ABC is 18 cm2. Side AC=4x AC = 4 x and side AB=x+3 AB = x + 3 . Given that angle A=30∘ , calculate the value of x

x = 3

Step-by-step explanation:

Let the altitude from B to AC intersect at point D.  Then BD is a height of the triangle with base AC

ΔABD is a 30-60-90 triangle since m∠A = 30

Therefore, AB = 2(BD)  or BD = AB/2 = (x+3)/2

Area of the triangle = bh/2 = AC(BD)/2 = 4x(x + 3)/(2)(2)

= x(x + 3) = 18

(x + 6)(x - 3) = 0

x = -6  or x = 3

x cannot equal -6, so x = 3

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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figure c

step-by-step explanation:

hope this .