Find dy/dx in the following
1) y=x^[10] +10^[x] +e^[x]
2) y=㏒ x +e^[x]+√x - 1/x

1. in picture 1

2. in picture 2

Hope this helps :T

Also I am not so shure about 2, but I am 98% shure 1 is right.

understand that i don't know the answers

will someone answer his question

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.