Mathematics, 01.02.2020 00:00, ray109
Find the values of x between 0 and 2pi where the tangent line to the graph of y=sinxcosx is horizontal.
Answers: 2
![\bf y=sin(x)cos(x)\impliedby \textit{now, using the product-rule} \\\\\\ \cfrac{dy}{dx}=cos(x)cos(x)-sin(x)cos(x)\implies 0=cos(x)[cos(x)-sin(x)]\\\\ -------------------------------\\\\ 0=cos(x)\implies \boxed{\measuredangle x= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}}\\\\ -------------------------------\\\\](/tpl/images/0491/6703/2b48a.png)
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Find the values of x between 0 and 2pi where the tangent line to the graph of y=sinxcosx is horizont...
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