Twice the greater of two consecutive odd integers is 13 less than three times the lesser number. find the integers.

let the first odd no be (x+1)

the other odd no is (x+3)

2(x+3)=3(x+1) - 13

2x+6 =3x+3-13

2x+6=3x-10

6+10=3x-2x

x=16

the first no. is 16+1=17

the second no. is 16+3=19

hi there!

the answer will be d: 2