Find two consecutive odd integers such that 77 more than the lesser is six times the greater.
the lesser consecutive odd integer is _ and the greater consecutive odd integer is _

The answer to your question is : number 1 = 13    number 2 = 15

Step-by-step explanation:

# 1 = 2n +1

# 2 = 2n +3

Conditions:

2n + 1 + 77  = 6(2n + 3)            

Simplify              2n + 78 = 12 n + 18

Solve it for n       12n - 2n = 78 -18

                            10n = 60

                              n = 60/10

                              n = 6

But

     # 1 = 2n + 1 = 2(6) + 1 = 12 + 1 = 13

     # 2 = 2n + 3 = 2(6) + 3 = 12 + 3 = 15

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!