Indicate in standard form the equation of the line passing through the given points. r(3, 3), s(-6, -6)

First find slope

slope=m=(y2-y1)/(x2-x1)

m=(-6-3)/(-6-3)

m=-9/-9

m=1

Point slope form is y-y1=m(x-x1) where m=slope and (x1,y1) is any point on the line so using m=1 and (3,3) we have:

y-3=x-3 but the standard form is ax+by=c so we need to solve for the constant...

y-3=x-3  subtract x from both sides

y-x-3=-3  add 3 to both sides

y-x=0  and x should have a positive coefficient...divide both sides by -1

x-y=0

You want to isolate your variable.