Acertain bacteria is growing at a rate of 4 percent each day. if the culture of bacteria has 5,000 bacteria today, how many bacteria will be present 10 days from now?

This is the concept of exponential growth, To get the number of bacteria after 10 days we use the formula:
f(t)=ae^(kt)
where;
a=initial number=5000
k=constant of proportionality= 0.04
t=time=10 days
f(t)=future number
thus the number of bacteria in 10 days will be:
f(t)=5000e^(0.04*10)
f(t)=7,459.12
The answer is 7,459.12

We know that the culture of bacteria has 5,000 bacteria today.
Also : p = 4 %  = 0.04, and t = 10 ( 10 days from now )
The formula is:
A = P * ( 1 + p )^t
A = 5,000 * ( 1 + 0.04 ) ^10
A = 5,000 * 1.04^10
A = 5,000 * 1.48
A = 7,401
There will be 7,401 bacteria.

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Answer: d. 48 step-by-step explanation: i used a calculator so i am 100% sure these are right   mark as brainliest?