What is the equation in point-slope form for the line parallel to y = -2x + 10 that contains j(6, 8)? a. y - 8 = -2(x - 6) b. x - 8 = 2(y - 6) c. y - 8 = 2(x - 6) d. y + 8 = -2(x - 6)

Hello mate!

A linear equation has the form y = ax + b

where x is the variable, a is the slope and b is the x-intercept.

We want to find the pararel line to y = -2x + 10

A paralel line of this, will be another line with the same slope ( -2 in this case) and a different x-intercept; then our line has the shape of:

y = -2x + b

and we know that this line pases through the point (6,8), and with this info we could find the value of b:

8 = -2*6 + b

b = 8 + 12 = 20

then y = -2x + 20 is the pararel line that passes through the point (6.8)

Then the correct answer is the option a:

a) y - 8 = -2(x - 6) = -2x + 12

y = -2x + 12 + 8 = -2x + 20

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

thats not a system of equations, that is a solution