Given 4x – 8y = 8:
a. transform the equation into slope-intercept form.
b. find the slope and y-intercept of the line.
c. find the equation, in point-slope form, of the line that is perpendicular to this line and passes through the point (1, 2).

4x - 8y = 8
a.  slope - intercept form y = mx + b
     subtract 4x from both sides.
   -8y = - 4x + 8
   divide both sides by -8
   y = (-4x/-8) (8/-8)
   y = 1/2x - 1

b.  slope (m) = 1/2
     y - intercept (b) = -1

c.  perpendicular slope = -2
     point ( 1,2)
     point-slope formula y - y1 = m(x - x1)
     y - 2 = -2(x - 1)