For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g) . E∘=0.483 V2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g ). E∘=0.483 V what is the cell potential at 25 ∘C∘C if the concentrations are [Co3+]=[Co3+]= 0.324 MM , [Co2+]=[Co2+]= 0.158 MM , and [Cl−]=[Cl−]= 0.384 MM , and the pressure of Cl2Cl2 is PCl2=PCl2= 5.80 atmatm ?

Explanation:

We must use the Nernst equation

The equation for the cell reaction is is

2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)

Data:

E° = 0.483 V

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C

n = 2

F = 96 485 C/mol

Calculation:  

T = 25 + 273.15 = 298.15 K

b is the correct answer

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answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol