Solve the equation g(x) = 2k(x) algebraically for x, to the nearest tenth. given
g(x)=2x^+3x+10
k(x)=2x+16

Using the degree of freedom rule, we can solve three unknown variables if and only if the number of independent equations is equal to 3. Thus the number of equations should be equal to the number of variables. We can use substitution to find x. 

g(x) = 2k(x)          (1) 
g(x)=2x^+3x+10  (2)
k(x)=2x+16          (3)

we substitute 2 to 1 and also 3 to 1. The resulting function hence becomes:
2x^+3x+10 = 2 * (2x +16)
Simplifying the equation on the right.
2x^+3x+10 = 4x +32
we group then the like terms on one side. That is,
2x^+3x - 4x+10 -32 = 0
2x^2 - x - 22 = 0 
The factors using the quadratic equation are

x1 ==1/4+1/4√177
x2 ==1/4-1/4√177

Hmmm i had this before , give me a sec