Abullet of mass 3.7 g strikes a ballistic pendulum of mass 4.6 kg. the center of mass of the pendulum rises a vertical distance of 19 cm. assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

v = 2401.09 m/s

Explanation:

It is given that,

Mass of the bullet,

Mass of a ballistic pendulum,

Vertical distance, h = 19 cm = 0.19 m

Here, the conservation of energy follows as the kinetic energy of bullet is converted to the potential energy as :

..........(1)

V is the speed of the bullet and the pendulum at the moment of collision.

Using the conservation of linear momentum as :

v is the speed of the bullet before collision.

v = 2401.09 m/s

So, the bullet's initial speed is 2401.09 m/s. Hence, this is the required solution.

15.3 cos 65 degrees trig

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