The figure below shows the net of a triangular pyramid. the given height is rounded to the nearest hundredth. if all the triangles are equilateral, what is the surface area of the pyramid in square centimeters? height: 4.33 cm base: 5 cm. *the net shows 4 triangles but i think one of them is the base of the triangle.*

43.3 square inches

Step-by-step explanation:

Formula for Triangle: A = bh/2

Key:

* = multiple

/ = divide

Fill in the formula with what you know:

A = bh/2

A = 5 * 4.33 / 2

A= 21.65 / 2 = 10.825 square inches

However, 10.825 is not our answer. 10.825 is the area of only one triangle. Since all four of the triangles are congruent (or the same) we can:

Add: 10.825 + 10.825 + 10.825 + 10.825 = 43.3 square inches

OR

Multiple: 10.825 * 4 = 43.3 square inches

Thus, the surface area of the pyramid is 43.3 square inches.

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

graph them on a graphing calculator, press 2nd trace. select intersect. hit enter until it says answer. ti 84 works best

step-by-step explanation: