Square a has a side length (2x-7) and square b has side length (-4x+18) how much bigger is the perimeter of square b than square a?

To make things easier, we can assume a value of x in order to substitute to each expression and obtain the side length of each. We can calculate for perimeter of each square. Then, compare them. We do as follows:

Assume x = 4
Square A
2x - 7 = 2(4) - 7 = 1
P = 4(1) = 4

Square B
-4x + 18 = -4(4) + 18 = 2
P = 4(2) = 8

Therefore, the perimeter of B is 2 than the perimeter of A.

6/ 11 = 0.545454 so your answer is55%