Suppose that a box contains 6 cameras and that 5 of them are defective. A sample of 2 cameras is selected at random without replacement. Define the random variable X
as the number of defective cameras in the sample.

Write the probability distribution for
X
.
k
P(
X
=
k
)
Correct
Correct
Correct

What is the expected value of
X
?

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol