Mathematics, 10.03.2021 23:40, des4273

Help m ASAP For one English test, Mary had 15 questions correct. She received a 72% on her test.

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Mathematics, 21.06.2019 16:30, angeline310

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane

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Mathematics, 21.06.2019 17:00, Will1119

How many credit hours will a student have to take for the two tuition costs to be equal? round the answer to the nearest tenth of an hour.

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Mathematics, 21.06.2019 20:30, nosugh

If m∠abc = 70°, what is m∠abd? justify your reasoning. using the addition property of equality, 40 + 70 = 110, so m∠abd = 110°. using the subtraction property of equality, 70 − 30 = 40, so m∠abd = 30°. using the angle addition postulate, 40 + m∠abd = 70. so, m∠abd = 30° using the subtraction property of equality. using the angle addition postulate, 40 + 70 = m∠abd. so, m∠abd = 110° using the addition property of equality.

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Mathematics, 21.06.2019 22:30, magics

Factor the polynomial, if possible. if the polynomial cannot be factored, write prime. 9n^3 + 27n^2 – 25n – 75

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Help m ASAP For one English test, Mary had 15 questions correct. She received a 72% on her test.