Suppose giving an isosceles triangle with a leg of 5 m two lines are drawn at some point on the base each parallel to one of the legs. Find the perimeter of the constructed quadrilateral

10

Step-by-step explanation:

im assuming that its an equalateral triangle because it makes the problem easier.

if you use the midpoint of the base as the point of where to make the parallels lines and draw them, you can easily find 4 congruent triangles, the side length of one of these congruent triangles is 2.5, and summing up the perimeter of the quadrilateral, you get 10.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer