Which of the following polynomials is in standard form? A. -4z-z16+z25+z14 B. x7+x5-4-x12 C. z10-5z-6z2+z3 D. y25-y22+y3-4

(a) x intercepts: -6 and 2

you can obtain these by solving the equation 0=x^2 +4x-12 using your favorite quadratic formula. but it is easy to verify -6 and 2 indeed satisfy this equation.

(b) y intercept: -12

this is obtained by setting x=0: 0^2+4*0-12 = -12

(c) the minimum value is: -16 (this is the vertex)

you can get the vertex by rewriting the equation into the form:

there is no global or local maximum as the function goes to infinity, so only in the limit sense: +infinity.

1-c

2-a

3-a

4-c

5-d

6-a

7-c

8-a

9-a

10-d

step-by-step explanation: