A bear loves visiting his friend, the piglet. The distance between their houses is 300m, and the bear always walks from his house to the piglet's house in exactly the same amount of time. But today, the bear stops at a beehive after walking 1/4 of the distance. He eats honey for 2.5 minutes and then continues to the piglet's house at a speed 15 m/min faster than usual. The total journey to the piglet's house takes the exact same amount of time as it usually does, when the bear does not stop for honey. How long does the journey take?

10 min.

Step-by-step explanation:

Remember d = rt

The distance from bear's house to beehive = 75m and 225m = distance from beehive to piglet's house

Let r = normal rate of speed

The normal time is 300/r without stopping

75/r = time from bear's house to beehive

225/(r + 15) = time from beehive to piglet's house

So, time from beehive to piglet's house + time at beehive + time from bear's house to beehive = normal time without stopping

225/(r + 15) + 2.5 + 75/r = 300/r

225r + 2.5r(r + 15) + 75(r + 15) = 300(r + 15)

225r + 2.5r^2 + 37.5r + 75r + 1125 = 300r + 4500 Let's remove the deceimal by multiplying thru by 10

2250r + 25r^2 + 375r + 750r + 11250 = 3000r + 45000

25r^2 + 3375r + 11250 =  3000r + 45000

25r^2 + 375r - 33750 = 0

25(r^2 + 15r - 1350) = 0

25(r - 30 )(r + 45) = 0

r = 30 or -45     But, the rate cannot be negative, therefore r = 30

The journey takes 300/30 = 10 min.

drop him sis he’s not worth your precious time