A shopkeeper bought an almirah from aWholesaler for & 5ooo and sold itfor $5700. Find his profit or less or persent
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c.p.= 5000

s.p.=5700

selling price is greeter than cost pries

then their is a profit

profit=S.p.- c.p.

p=5700-5000

so the profit was the rupees=700

the shopkeeper had a profit of rupees of 700.

Step-by-step explanation:

attachment?

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204