1. A rabbit can hop 6 feet in 2 seconds and 12 feet in 4 seconds. If the number of feet varies directly with the time the rabbit spends hopping, at what speed is the rabbit hopping?

The rabbit is hopping at 3 feet/ sec in speed

Step-by-step explanation:

Step 1

Let the The number of feet of the rabbit be expressed as N

AND  time rabbit spends hopping can be expressed  as  t

From the question,  The number of feet varies directly with the time rabbit spends hopping can be expressed  as

N α t

Let us introduce a constant of proportionality ,S which represents  speed in this case, we now have that

N = St

STEP 2 -- SOLVING

If the rabbit hop 6 feet in 2 seconds, Then speed =

N = St

6=  S X2

S = 6/ 2

S = 3

also

If the rabbit hop 12 feet in 4 seconds, Then speed =

N = St

12=  S X 4

S = 12/ 4

S = 3

Also recall

that Speed = Distance / time

Pluging the values in the first case,

speed = 6 feet/ 2 secconds = 3 feet/ seconds

in the second case

Speed= 12 feet/ 4 second s= 3 feet/ secs.

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6