A Mars rover descended from the rim of a crater at a constant rate. After 2 days, the rover's elevation was 106 meters. After 6 days, its elevation was 48 meters. What elevation did the rover start at? meters Complete the equation that describes the relationship between the rover's elevation in meters, E, and the elapsed time in days, t. Write your answer using whole numbers or decimals rounded to the nearest tenth. E= ___ t+

135

E = - 14.5t + 135

Step-by-step explanation:

Given that, descent rate is constant ;

Elevation after 2 days = 106 m

Elevation after 6 days = 48 m

Let

Rate of elevation per day= x

Initial elevation = a

Hence,

a - 2x = 106 - - - (1)

a - 6x = 48 ___(2)

-2x + 6x = 106 - 48

4x = 58

x = 58/4

x = 14.5 meters per day

Hence, initial elevation :

a - 2(14.5) = 106

a - 29 = 106

a = 106 + 29

a = 135

Relationship between Rover's elevation, E and elapsed time, t

E = - 14.5t + 135

-14.5 = rate per day

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

11

step-by-step explanation:

32.50-7.50=25

225/25=11