A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing at a constant rate of 4 m/s2. What is the magnitude of its total acceleration at this instant?

a. 3 m/s2
b. 4 m/s2
c. 5 m/s2
d. -5 m/s2

(c) 5m/s²

Total acceleration (a) of a particle in a circular motion is the vector sum of the radial or centripetal acceleration () of the particle and the tangential acceleration () of the particle and its magnitude can be calculated as follows;

a =           ---------------------(i)

But;

=      ------------------------------(ii)

Where;

v = instantaneous velocity

r =  radius of the circular path of motion

From the question;

v = 30m/s

r = 300m

(i) First let's calculate the centripetal acceleration by substituting the values above into equation (ii) as follows;

=

=

= 3m/s²

(ii) From the question, the velocity of the particle is increasing at a constant rate of 4m/s²  and that is the tangential acceleration , of the particle. i.e;

= 4m/s²

(iii) Now substitute the values of and into equation (i) as follows;

a =

a =

a =

a = 5m/s²

Therefore, the magnitude of its total acceleration a, is 5m/s²

the largest known star in the universe is uy scuti, a hypergiant with a radius around 1,700 times larger than the sun.jul 26, 2018

explanation:

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.