Two ships leaves a port at 8am. Ship A sails with a bearing of N 60 deg E at a speed of 10mph. Ship B sails with a bearing of S 52 deg E at a speed of 8mph. If the ship maintain their paths, how far are they at 1pm?
82.6mi
19.8mi
51.Omi
68.Omi

33

step-by-step explanation: g=6

$12. that is my answer.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

391.6 is the correct answer