Question 5 14 pts
How many solutions does the linear system have?
Hint: Solve by any method!
x- 4y = 2
2x - 8y = 5
There is [Select]
because
[Select ]

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.

  or  

sin y = 7/q

7 is the opposite side length, q is the hypotenuse

tan y = 7/r

7 is the opposite side length, r is the adjacent side length

using sohcahtoa ^^^^

cos y = adjacent/hypotenuse

cos y = r/q

x^2 + 10x + 38 + 161/x-4

to find this, you'll need to synthetically divide using synthetic division.

here's how you would set it up:

4 is what you're dividing by (set x -4 = 0)

the numbers you are 'dividing' by are 1, 6, -2, and 9 or the coefficients of the terms listed above.

bring the first term down (1), multiply that by 4 before raising it to the next term to add (6). repeat this process as so:

6 + 4 = 10; 10 x 4 = 40; 40 - 2 = 38 x 4 = 152 + 9 = 161

161 is over x-4 as there are now two constants and you cannot combine them.

also, i'm not sure if it was -9 or +9, so i assumed.

hope this !