Mathematics, 12.07.2019 03:00, jpaintballer1

Solve each equation. if an equation has no solutions or if an equation has infinitely many solutions, explain how you know. 15. 3x − x − 5 = 2(x + 2) − 9 16. 7x − 3x + 7 = 3(x − 4) + 20 17. −2(x − 2) − 4x = 3(x + 1) − 9x 18. 5(x + 2) − 3 = 3x − 8x + 7 19. 4(x + 3) − 4 = 8x + 10 − 4x 20. 3(x + 2) + 4x − 5 = 7(x + 1) − 6

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Mathematics, 28.08.2019 21:30, arizola757

Plz will mark brainliest a) equation creation use the expressions below to create one equation that has exactly one solution, one equation that has no solutions, and one equation that has infinitely many solutions. each equation should use two of the expressions—one on each side of the equals sign. a. 0.5(60)x + 5 b. 0.65(50)x c. 45x − 0.75(20)x + 5 d. 1.5(10)x + 15(x + 1) − 5 explain how you know each equation has one, none, or infinitely many solutions. show all your work and then write a 1-paragraph explanation of your thinking. use complete sentences and correct punctuation.

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Mathematics, 28.08.2019 21:30, Jennitiu

Plz will mark brainliest! a) equation creation use the expressions below to create one equation that has exactly one solution, one equation that has no solutions, and one equation that has infinitely many solutions. each equation should use two of the expressions—one on each side of the equals sign. a. 0.5(60)x + 5 b. 0.65(50)x c. 45x − 0.75(20)x + 5 d. 1.5(10)x + 15(x + 1) − 5 explain how you know each equation has one, none, or infinitely many solutions. show all your work and then write a 1-paragraph explanation of your thinking. use complete sentences and correct punctuation.

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Mathematics, 28.08.2019 21:30, dawsoncollins4117

Plz will mark a) equation creation use the expressions below to create one equation that has exactly one solution, one equation that has no solutions, and one equation that has infinitely many solutions. each equation should use two of the expressions—one on each side of the equals sign. a. 0.5(60)x + 5 b. 0.65(50)x c. 45x − 0.75(20)x + 5 d. 1.5(10)x + 15(x + 1) − 5 explain how you know each equation has one, none, or infinitely many solutions. show all your work and then write a 1-paragraph explanation of your thinking. use complete sentences and correct punctuation.

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Mathematics, 22.09.2019 04:10, davidaagurto

1. what is the value of x in the equation –6 + x = –3? (5 points) –9 –3 3 9 2. how many solutions does the equation –2a + 2a + 7 = 8 have? (5 points) one two none infinitely many 3. what is the value of y in the equation 2(2y – 16) = 0? (5 points) 4 6 8 9 4. how many solutions does the equation 5p – 4p – 8 = –2 + 3 have? (5 points) one two none infinitely many 5. the steps below show the incomplete solution to find the value of n for the equation 4n – 2n + 4 = –1 + 17: step 1: 4n – 2n + 4 = –1 + 17 step 2: 4n – 2n + 4 = 16 step 3: 2n + 4 = 16 which of these is most likely the next step? (5 points) 2n = 12 2n = 4 2n = 8 2n = 20 6. what is the value of z in the equation 2(4z – 3 – 1) = 166 – 46? (5 points) 14 15 16 17 7. what is the value of x in the equation –x = 3 – 4x + 6? (5 points) –9 –3 3 9 8. how many solutions does the equation 4n + 6 = 4 + 2 + 4n have? (5 points) two many none one 9. which of these is a simplified form of the equation 6y + 4 = 8 + 2y + 2y? (5 points) 6y = 8 10y = 12 2y = 4 4y = 12 10. the work of a student to solve the equation 3(2x – 4) = 8 + 2x + 6 is shown below: step 1: 3(2x – 4) = 8 + 2x + 6 step 2: 5x – 7 = 14 + 2x step 3: 5x – 2x = 14 + 7 step 4: 3x = 21 step 5: x = 7 in which step did the student first make an error and what is the correct step? (5 points) step 2; 6x – 12 = 14 + 2x step 2; 6x – 7 = 2(6 + x + 4) step 3; 5x – 2x = 14 – 7 step 3; 5x + 2x = 14 + 7 11. which statement is true about the equation z – z + 1 = z + 1? (5 points) it has no solution. it has one solution. it has two solutions. it has infinitely many solutions. 12. what is the solution to the equation 3.6m – 2.7 = –1.8m? (5 points) m = 0.25 m = 0.5 m = 1.25 m = 1.5

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