Plz will mark brainliest!
a) equation creation
use the expressions below to create one equation that has exactly one solution, one equation that has no solutions, and one equation that has infinitely many solutions. each equation should use two of the expressions—one on each side of the equals sign.
a. 0.5(60)x + 5
b. 0.65(50)x
c. 45x − 0.75(20)x + 5
d. 1.5(10)x + 15(x + 1) − 5
explain how you know each equation has one, none, or infinitely many solutions. show all your work and then write a 1-paragraph explanation of your thinking. use complete sentences and correct punctuation.

First, let’s simplify all the given equations.

A: 0.5(60)x + 5
30x + 5

B: 0.65(50)x

32.5x

C: 45x - 0.75(20)x + 5
45x - 15x + 5

30x + 5

D: 1.5(10)x + 15(x + 1) - 5
15x + 15x + 15 - 5

30x + 10

Exactly one solution:
For an equation to have exactly one solution, you must be able to solve for x.
A, C, and D all have 30x in their equation. Meaning, if you equated them, you would either end up with a false statement or a true statement.

Therefore, we have two possible equations that has one solution.

30x + 5 = 32.5x
30x + 10 = 32.5x

No solution:

For an equation to have no solutions, the equation, when simplified fully, must be a false statement. Combining A and C will result in an equation with infinite solutions( will discuss later)

However, both A and D have the same coefficient but different integers.

30x + 5 = 30x + 10

When simplified, you result with 5 = 10, which is false. Any equation that simplifies to a false statement has no solutions.

Infinite solutions: an equation with an infinite set of solutions will simplify to a true statement. We notice that C and A, after simplification, are the same.

30x + 5 = 30x + 5

After simplification, 5 = 5, which is true. You can try plugging in any value for x and it will always be equal.

Hold on lemme do the work