Using the elimination method how do I find x and y for the following problem: 4x-7y=13
4x + 7y = -29

8x= -16

x=-2

Step-by-step explanation:

1. add 4x+4x=8x

2. subtract -7y+7y=0

3. subtract 13-29= -16

4. divide -16 by 8x= -2

you basically align the variables and solve down.

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.