ANGLE RELATIONSHIPS Puzzle Drections Solve the problems along the bottom andraht edge of each square foume alines
that appear to be ntersecting are interesting Then cut the squares apart and arrange them
so the edges match Paste the squares on the templaten the correct order
67
49
B
19
118
Classify Zx and Ly
M
Find mer
Find mzx
51
y
Find my
Classify Ly and Zz
118"
Find my
58
D
E
141
F
799
y
(9x + 5)
Find mzx
Supplementary
Find mzr
46
y
(12x-37)
Solve for x
у
86
103°
41"
Find my
Find my
43°
Find my
28°
G
H
156
(17x + 7)
y
(9x + 5)
Solve for x
(3x - 1)
(15x - 17)
129
13
Solve for x
6
Solve for x
(13x + 1) (7x + 19)
y
Find mZy
Find my
Find my
Vertical
J
105
K
L
133
Y
עי
(5x - 14)
(10x + 38)
127°
Solve for x
14
(5x + 2)
(8x - 25)
Solve for x
Complementary
Solve for x
21°
(18r - 2)
*(x + 8)
Find mzy
Find mZy
Find mZy
Gina Wilson (All Things Algebra), 2015

he spend 5.1 minutes chatting with his friends

step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)